The Great Four

Discussion in 'World Boxing Forum' started by War-Lord, Apr 8, 2013.

  1. War-Lord

    War-Lord Active Member Full Member

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    Who was the best in their respective primes.
     
  2. Imperial1

    Imperial1 VIP Member Full Member

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    Barrera !
     
  3. xRedx

    xRedx Boxing Addict Full Member

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    this kinda copies the fabulous four duran,hearns,hagler,leonard but i still like it. heres a documentary on it, i liked it.

    [yt]OwEb-ShRjy4[/yt]
     
  4. War-Lord

    War-Lord Active Member Full Member

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    Thats very well done.
     
  5. BobDigi5060

    BobDigi5060 East Side MMA Full Member

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    Juan Manuel Marquez.

    He fought everyone, including both Mayweather and Pacman. Didn't have the matchmaking help him through these past few years either. Also, he's got more tools and longevity than the other three fighters.
     
  6. Abdullah

    Abdullah Boxing Junkie banned

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    Pacquiao
     
  7. uberstar

    uberstar Guest

    pac, morales, barrera, marquez
     
  8. War-Lord

    War-Lord Active Member Full Member

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    Trying to bump this so people won't post on the other thread.
     
  9. Milpitas

    Milpitas Guest

    1) Pacquiao
    2) Morales
    3) Barrera
    4) Marqoid
     
  10. eviltaker10

    eviltaker10 Active Member Full Member

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    The Fact that you Put Pacquiao on top and then Marquez at the bottom while calling him "Marqoid" clarifies to me that you are a ******* :-:)-(
     
  11. elchivito

    elchivito master betty Full Member

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    1. Morales
    2. Marquez
    3. MAB
    4. Pacman
     
  12. BobDigi5060

    BobDigi5060 East Side MMA Full Member

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    MAB > Morales.
     
  13. xRedx

    xRedx Boxing Addict Full Member

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    lol.
     
  14. War-Lord

    War-Lord Active Member Full Member

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    How is this even logical?
     
  15. xRedx

    xRedx Boxing Addict Full Member

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    I have it:

    Morales
    Pacquiao-Marquez
    Barrera

    Morales would come out with the most victories and least losses against the other 3 in my view. pacquiao and marquez are even whereas barrera at the bottom.

    this is based on h2h between the 4.