Calzaghe vs Ward break down of strengths? Very even across board

look like u blew your top again, 6 replies in a row ranting, and all wrong again. Hahaha.

 

haha i like how you laugh at yourself because he beat kessler like joe did at home. oh hi yeeaah but better job of it.

 

and still joe ran from froch! even more howardzaghe. you make it worse for him.

 

yeh I can see why chose to reply with zero content, its an improvement on your other posts.

i might even like it for you, your best post in ages.

 

To fight a p4p fighter so now a guy who's struggled with Brian Magee should be considered over a P4P fighter?

Is that what you are saying?

 

Did Joe lose to Kessler?

 

No just finishing work, have you been work today?

 

ahahahah Magee was 2006, not 2008, you got a time machine mate? u flop, you dont wangle out of your mistake by pretending three years dont exist.

no wonder you ran away earlier, and lost your rag when you came back. I'd lose my rag if my argument ignored 3 years.

 

why, do you want a medal for it? hahaha

 

not abroad he didnt, becasue that didnt happen he ran from the rematch!

ahahahaha, you keep botching your own arguments!

 

Well yes considering my taxes are paying for parasites like yourself.

 

Did he lose to Kessler yes or No?

 

Oh I'm sorry not Brian Magee he was fighting the legendary Albert Rybecki....I take it that is better than Hopkins?

 

Rodriguez isn't that great, he's just better than most of the slop Joe faced. And it is convenient that Kessler was over the hill vs. Ward yet only "semi-shot" a year later when he faced Froch.

Joe has one A level win in Kessler, a B+ in 44 year old Hopkins, then nothing else of note. He was an interesting, awkward guy. But his fans insistence that he was some type of world beater draws him a ton of backlash.

 

So Rodriguez is better than

Eubank
Brewer
Bika
Kessler
Reid
Mitchell
Lacy
RJJ
Hopkins
Woodall

Hell even Omar Sheika is better than Rodriguez.

I tell you what, rate Sheika's top wins with Rodriguez and get back to me.