BMI and waist measurements are not evaluating physical fitness. They're assessing a person's health risks. The BMI is the starting point; it reflects your relative weight for your height and is generally associated with body-fat percentage.
You're a bit off-topic. We're talking about physical advantages here, not fight outcome. Again, waist size reflects the relative weight for your height and is generally associated with body-fat percentage, which is used to assess health risk.
physical advantage of course belongs to hatton. he is bigger and well-settled at 140. pac only has two fights above 130 and never at 140.
I think Pacs the best fighter in the world & have done since he stopped Barrera but Hatton is just too strong & not an old slug like De La Hoya
A physically fit athlete will always have an advantage towards a non-fit one. BUT the outcome of the fight is a different thing altogether. Remember that De La Hoya has the physical advantage over Pacquiao. Look at the outcome. There are so many intangibles in fighting. Strategy, Skill, In-born talent, luck, etc. Boxing after all is part art, part science. Still, its better to have an advantage than none at all.
are you telling us that a fighter with a smaller waist has the advantage in waist department? i just don't get it. pac has the larger chest, he has the advantage in the chest dept., he has the larger biceps so he has the advantage in the biceps dept. but when it comes to waist, its the reverse? :? (just pointing out that pac has the smaller waist of the two, so hatton must've the advantage)
De La Hoya had the size advantage but Pac had the speed which is very important plus pacs very powerful which evens out the size thing
didn't you get my point? i'm talking about the waist department, pac has 28" waist and hatton has 30". why the hell pac has the advantage? is it an error?