Will Pacquiao be the first boxer to STOP Mosley?

Mosley is going to come out strong from the get-go and might hurt Pacquiao if Pacquiao is not careful but I see Pacquiao winning in the later rounds, and possibly knocking Mosley out. Mosley seems to get tired quick now days.

 

How about Oscar?

 

Doesn't matter if Mosley is old or not, as long as he is in his optimal stance he is dangerous to everyone out there (almost dropped Floyd twice). Once Pacquiao gets to the late rounds I see him stopping Sugar.

I also believe he might pull an upset, why not he almost did against Floyd. The fight itself will reflect in how Floyd vs. Manny would go.

I know that "almost" isn't the right word but he managed to hit Floyd clean with his power punch.

 

Oh the mind of a hater ...


So if PAC being the first one ever to stop Mosley isn't worth "**** all", then what's Floyd getting rocked by Mosley early then cruising to a UD worth ? Hmmm?

 

At least $22.5 million.

 

The only way this goes the distance is if Pacquiao carries Mosley which is a likely outcome. What's most likely is Pacquiao stopping him though.

 

Hahahaha GOAT said fart

 

I love that guy!

 

After getting headbutted. Still, that right hand Forrest nailed him with was mean.

 

:thumbsup
That guy had a serious question which required a honest answer :good

I don't think the wind knew which way his question was-a-blowing.

Good to see ya Dddduuuuddddee! Looks like Chisora still winning big against Waldo !

 

If it stops it will be by refvor corner. Mosley would shrugg off any of pacs shots

 

That is the only interest in this fight for me. Will Shane last?

IMO I think he will.

 

jmm was the first man to stop cassamayor. What was that worth?:think

 

That was a great win for jmm , I don't know what point you're trying to make . You're idiot if you think PAC stopping Mosley isn't impressive. Mosley has quite a resume and has only ever been in trouble once.

 

Mosley is washed up now. It always comes a time when an old fighter finally is finished off.