Now he's the WBC champ who do you think he should fight next and what fighters will be looking to take him on?
I think he should avoid Calzaghe as he would murder him with his work rate but with his iron chin I reckon he could mix it with most the rest of the division.
I would like to see him take on Taylor. Froch does have an excellent beard, but he needs to keep his left hand up and be a little more active with the jab, IMO. Still, it was an excellent fight and he fought very well.
I thought he would have more in the tank in terms of stamina and output. Basically if he moves to unify, he will be battered by Kessler, lose to Bute and lose to Taylor. I called Froch by KO against Taylor only weeks ago and felt that he would be behind but land the shot, but after tonight he clearly does not carry his power late when he is tired. He has a punchers chance against Taylor and nothing more. Pavlik I think he KOs. Froch has a granite chin and he can punch, Pavlik is not going to box him, he will fight and the intangibles say Carl wins.
Plenty out there for him, plenty of hard to pick fights. Exciting division now. Pascal will have another chance too.
Good victory and the names already mentioned above are all good fights. He will be good value because of his low hands, and the fact he is easy to hit with a good chin. I always thought his power would be his main tool, but against the top 5 guys in the division, he may find they take the shots just as Pascal did tonight.
I think Taylor would whoop him by decision. I would watch it with glee, but think Taylor would definetly win.
I'd like to see Froch in big fights. Taylor, Kessler, Bute, Andrade would all be good. Or perhaps Inkin btu I doubt they'd be too keen to give him a fight after being cocked around by him. Froch Andrade would be a guaranteed war.
I think Kessler beats him not sure about Bute and I think he definitely has a chance against Talyor as Taylors focus can wane. I'm sure though he'll be looking for Taylor to get some HBO time and afer that fight he'll be good value.