I will be. Would rather watch the Cotto-Margarito fight, but this one could be just as good and maybe better.
Showtime offers the better package and it offers it for free. Mares-Agbeko I was a WAR too and just like HBO's match-up, it has unfinished business written all over it. But unlike Cotto-Margarito, a damaged goods fight unfortunately, Mares-Agbeko is a prime showdown although the other will be very good two. Totally packed weekend. Choice should be yours, but if you can't afford the PPV you're still going to be treated superbly, so watching Showtime and catching the Margo fight on replay might be the smart choice.
I honestly can't see how Mares can win the fight without going low again. He does it that often it must be ingrained in his muscle memory.
I am going to record it on the DVR. I have to roll with Cotto-Margarito. I am hyped about Helenius-Chisora too. I think Mr. Helenius just might be the Heir Apparent to the Klitschko's. Remember where you heard it.
mares-agbeko 1 was a war? The cotto card is the one to watch cotto vs margo - fight of the year candidate Rios vs Murrey - will be short and sweet Rodriguez vs Wolak - polish glass shattered all over the canvas (just hope one of the other fighters dont get cut by wollacks glass) Mike Jones vs Lujan - Mike Jones quick ko.
I'd rather watch free Agbeko v Mares than pay to see two past-it fighters fight to the same result as the first fight.
you're not paying showtime subscription? most people are just saying it to act rebellious against BOB the super G Arum but mother****ers will be tuning in to watch seriously who likes watching 2 guys the size of bitches punch each other in a small arena?
Yeah, I"m also paying an HBO subscription, so I'm sure as **** not going to pay another $49.95 on top of that. Cotto and Margarito are done. Watch a fight that actually matters in the sport.
It's free on regular television over here on channel 7. This is so rare, it'll be the first time, so it's a great opportunity for Oz boxing fans to check it out and good for boxing.