No, it's impossible. Situation 1 Fighter A gets knocked down once, Fighter B gets knocked down once. Fighter A has the better overall round Score: 10-9 for Fighter A Situation 2 Fighter A gets knocked down twice, Fighter B gets knocked down once You score the round: 10-8 for Fighter B Situation 3 Fighter A gets deducted 1 point for a foul but wins the round, Fighter B loses the round but does not get knocked down Score: 9-9
10-10 in the event of both fighters being dropped and the round being even. However, you don't usually see 10-10 rounds because even rounds are kind of a cop out for most professional judges. They'll see it one way ever so slightly even if it was a really really even round.
Don't need to tell me that twice. The other day I had to rupture my Father's liver as he was disrespecting me by insisting that donating to charity is important, the nerve of that man.
I mentioned a boxer dominating a round and THEN getting knocked. A boxer can dominate a round, have his opponent on the verge of being stopped who then lands his only meaningful punch of the round which results in a knockdown. In that case, I would give the round to the boxer who was floored.
And even then by my understanding the point is deducted from the total not the round and it would be scored 10(-1)-9. With the 1 deducted from total score
