Marquez is a great fighter and his win against Pacquiao was a great win. However I would have to favor Oscar who has wins where he’s taken the belts from JCC sr and Pernell Whitaker or unified with Vargas. Even if you factor in JMM questionable losses against Pac then you would negate that with Oscar’s loss to Trinidad. Not to mention victories over Genaro Hernandez, Ike Quartey and Ricardo Mayorga. Oscar’s career has become severely underrated as of late.
This is a really good question and also hard to decide given both of their great resumes. ODLH has wins over Chavez, Whitaker, Camacho, Quartey, Vargas, Hernandez, Carr, Mayorga JMM has wins over Pac, Barrera, Casamayor, Diaz, Salido, Juarez, Katsidis Honestly you can make a case for both. Might have to pick ODLH slightly. Despite what you might think of him he really did fight everyone, even if he did lose some big fights. Wins over Chavez (x2) and Whitaker is enough to pick ODLH over JMM.
Tough one. Oscar tends to get underrated. This probably depends a lot on how you scored JMM-Pac in the series. If we were to rank their best wins: 1. JMM-Pac 4 2. JMM-Pac 2 (7-5 JMM on my card) 3. JMM-Pac 3 (8-4 JMM on my card) 4. De La Hoya Trinidad 5. De La Hoya-Whitaker 6. JMM-Barrera 7. De La Hoya-Quartey 8. De La Hoya-Chavez 9. De La Hoya-Vargas 10. Marquez-Casamayor 11. De La Hoya-Mosley 2 (DLH won on my card) 12. Marquez-Salido Whenever I list them like that, I like to add a descending number of points. Normally I'd just assign the inverse of the ranking, but since doing so here would give Marquez perhaps more credit than he deserves for defeating the same man 3 times, I'll make each Pac win 10 points. JMM: 10 + 10 + 10 + 7 + 3 + 1 = 41 pts DLH: 9 + 8 + 6 + 5 + 4 + 2 = 34 pts It's worth nothing that Oscar has won titles in 6 divisions to JMM's 4, though Marquez would have won a historic 5th had he been given the 3rd Pacquiao decision.
This is a good thread. I would say slidght edge to de la Hoya career wise. Even though I’m a huge Marquez fan. Oscar has the greater resume.