Amir Khan Vs Juan Manuel Marquez; Who wins and why?

Is that based on Marquez never being KO'd before, or based on the best fighter Khan has ever knocked being Salita?

 

I see that fight being very similar to JMM-Diaz. Khan will have his moments, but eventually will wilt under pressure.

 

Marquez cracks that glass. It shatters.

 

Tooo much pressure from Marquez.He should be able to figure Kahn out by mid fight and start to land his long counters.Not a s shot as people think.Too much experience,ring smarts and heart for a young Kahn.

 

Surprised by the amount of people who feel Kahn will beat Marquez. Just because he was dominated in his last fight by one of the best out there, doesn't men he won't tear Kahn a new one. Marquez is too skilled and crafty for the defense averse Kahn. It'll be interesting, but Marquez walks away with his hand raised in this one.

 

Marquez beats that khan A$$ anyday of the week! A lot of underestimating of JMM, this man was ducked for the larger part of his career, for his pure skill, and will to win even when the odds are against him.

JMM by mid-round KO!

 

At 130, JMM eats Khan for breakfast. At 135, closer but the same result. At 140, it's a very interesting fight. I think Kahn's choice to campaign at light welter is a good one, and is more suited to his body frame.

Khan: Youthful energy, brilliant handspeed, good heart, disciplined, Roach.
JMM: All-round great fighter, lots of ring-smarts, good chin, great recovery. Can counterpunch-box, but can trade with the best of them when he has to. Hits hard for a little 'un.

Like I said in another thread, I can't see Khan dropping Marquez (but he could surprise me), which means he has to go 12 rounds with him. And, if he has to go 12 rounds with him, I can't see Marquez not catching Khan with something big and nasty at some point.

I'm going with JMM, but the higher weight does worry me a bit.

 

Marquez has no buisness being at 140....he should max out at 130 and really should have his ass at 126. Kahn will beat his ass because of this.