Bradley: there’s no way in hell I can beat him every round

Of course he isn't confident, he knows Pacquiao should have got the decision in their first fight and it was a robbery that he didn't. He knows Pacquiao is gonna bring it HARD and not leave it up to the judges to rob him again. I foresee a vicious Pacquiao KO win inside 10 to bring this Bradley hype train crashing to a halt.

 

True!
:good

 

But anyway i like bradley he fights anyone noone can take this from him! Not cherry picking he know he can loose and still go out and fight pacman

 

Bradley's got this. I'm a huge PAC fan but if Bradley managed to push PAC the way he did with a Fukd up ankle I think he can beat him injury free. I think there's still more improvement from Bradley where as PAC is on the slide and the main thing with brad he fights better against a better opponent

 

He might have had a mashed up ankle but he was also fighting a PAC who was coasting like he DGAF

 

If we get the Pac who was beating up Marquez in their 4th fight then Timmeh' is doomed. He hasn't got the 1 punch power to drop or KO Pac like Marquez did.

 

Knowing its coming from Bradley, its more respect - he's one of the most respectful fighters i can ever remember


I have no idea who wins this

 

I think were gonna get that version of MP

But that was a shot version of JMM

Tim is prime, and at this stage, he's not only way faster than Juan, he's faster than Manny too

 

Nice, because I don't see 'it' in Bradley, never have understood what was so great about him.

 

I think it's not really a lack of confidence so much admitting Pac is going to land solidly enough to win some rounds with his speed and power, since one decent shot from Pacquiao pretty much equates to five from Bradley.

 

This fight will be far from exciting but it will be interesting.

Bradley will be more confident this time around and will keep the fight close this time.

 

Y'all underestimating Tim

Americas greatest fighter

And he gets **** all respect

:-(

 

Ducked Khan!

 

Close thread.