When Pac moved up to WW and beat Oscar, I remember that I thought Shane was the only WW that would take Pac out, I believed Floyd would UD him. But now a lot of time has passed and both opinions have changed. Prime for prime I favour a Mosley KO, but it's been a while since he looked good. I'm not saying he's shot, just declining. And anyone who uses Cotto as a measuring stick is an idiot. That was a pre-plaster beaten Cotto Shane got in there with and it was a damn close fight. He already proved those wrong by beating the crap out of Tony.
**** no Im not. He's slowed down. The Margarito fight, that was his last great performance, probably the best of his career Against Mayweather, you could finally see his age. He was slower, he didnt fire off punches like before. It happens to most every fight as they age, they lost that razors edge reaction time. It was clearly noticeable against Mora Its been said before, a fighter will get older, will describe how he sees the openings, knows he should throw punches, react, move, but his body doesnt move with the same speed, his reaction time isnt the same That happened to Mosley, and against Pacquaio he's going to get torn apart by a hurricane of powershots from every ****ing angle with sickening speed.
Mosley has that big right hand and Pac is a southpaw. So it is possible.... But I just don't see Mosley handling Pac's speed at this late stage of his career. He won't be stopped, but Naz may very well pull him out.
Mosley harder and faster puncher than Margarito, Pacquiao stay off the ropes or Buboy gon start crying. Mosley ill give about 15% chance on winning.
shanes best chance is inside 6 rounds, after the 6th round i can see shane taking a serious beating and his corner may even have to stop the fight
The only way shane doesnt get stopped is if he runs or covers up because he cant take pacs power shots for 12 rounds like the MANSTER (margarito)!
The This content is protected shot he is getting is from whoever is supplying him with roids or whatever else he takes to perform at a higher level.