Pacquiao vs rios november 23

Rios is going to finish Pac

 

Source?

If true it's a joke, surely Alvarado is a better option or the guy Bradley just faced for Pac to batter him to hype a Bradley rematch.

 

Damn man. Alvarado got ****ed out of a payday.

 

Would have prefered if Alvarado fought Pac. Mike must be thinking WTF, I should get that shot. Also I think Rios would have benefited from fighting someone else hes coming off a loss. Is there a venue confirmed???

 

I don't mind the fight. It should be action packed. The winner gets his career right back on track.

 

Entertaining fight but I feel for Alvarado. :-(

 

sort of the truth. The guy who wins doesn't get the big fight. Although Rios vs. Pacman is a more exciting fight to be honest. This is a risky fight for Pacman, yet his handspeed is just to much for Rios.

 

Rios getting ktfo. Doesn't have the skill to deal with PAC

 

Pac fighting another guy coming off a loss?

 

Was hoping for Rios-Provodnikov.

But this will be a great action fight too.

 

Can't find this confirmation anywhere.


If Pacquaio has 40% left which I expect he has, then he stops Rios. Brandon had trouble with the movement of ALVARADO.

 

Good matchup. Pac's career is on life-support having experienced almost three back-to-back losses, and so matching him up with a bitter Rios who's durability is second-to-none, will be a good parameter to see what Pac has left. It'll be an action-packed fight.

 

Alvarado likely gets the winner. He'll fight at home, get a big crowd. Rios and Pac fight in Macau and the winner takes on Alvarado.

Arum gets himself three nice in-house fights.

 

Don't feel too sorry for Alvarado. It's not like he's being left completely out to dry. He'll likely be rewarded with a winnable opponent next -- to help recover from the back-to-back wars he's been having -- and still be in the mix for Bradley, JMM and the Pac-Rios winner. Bob Arum has to make the most out of these few WWs he has left. The last thing he'll do is keep one of them out of contention.