Tyson Fury vs David Price???

Price would be ripe for picking at this point

 

IMO it would be a easy fight for fury I think prices power is overrated his only ever knocked out trash

 

Allen would be a good 12 rounds for Tyson. You know he isn't stopping him because Allen has cast iron jaw but nor is Allen landing anything dangerous on him. Would be ideal.

 

I hink like Ortiz Tyson would stop him. Fight wont happen as Allen had came out and said he won't fight someone he knows he can't beat as that is not the man he is. Said he fought Ortiz because he actually thought he could win.

 

Tyson showed in his victories against Hammer and Chisora that if he can’t knock you out, then he can make you quit. He’s all about the skills. He’s mostly always in control with his movement, his range, his jab...when you have those skills, you don’t need to plant your feet and try and put your opponent to sleep. If it happens it happens.

 

Great post. He's one of those fighters that takes a guys soul. They train hard for 8 weeks, do everything in their power to beat him but can barely land a punch. And because their heavyweights, the gas tank can go and by 10-12, they and their corner want it over with.

 

I think its overated too. Touted as the heaviest puncher in the division a while back, bit ott. He hasn't even got a half decent punch now down to confidence.

 

I don't think Allens good enough even for Fury's return. Also if Tyson couldn't stop him, I would be concerned. I'd prepare a bit longer and comeback against a known name, not Allen

 

Tyson wouldn't stop him, 90% of HW's won't stop Allen. It's not Fury's game either, he doesn't go looking for KO's. The full 12 rounds would be good for him.

 

Give over. Tyson wouldn't spark Allen, but any ref/cornerman who allowed him to go past ten would have to be expelled from boxing. See Chisora/Hammer fights for reference, two better fighters than Allen. Fury ain't got KO power, but he'll punish anyone outside of the elite round after round til they have to be pulled out.