Cotto: Elite WW?

elite but not an ATG at WW

 

Look at this tight ass mofo pretending to be a professor like Nallege.

Cotto was an elite welter in his era but hes not elite if you compare him with the ATG at welter.

Happy now?

 

Are we talking ATG or elite?

I thought you mean elite in context with the CURRENT welters. I say definitely yes.

If you are talking about ATG 10 in WW, hells no.

 

Of course he is, can't give top fighters good enough challenges if he's not elite.

 

NO! But for this era of WW's absolutely. There are only 3 active WW's that could be mentioned with the likes of Leonard and hearns, Gavilan....Shane, Floyd and Manny....And I'm not 100% sold on manny at this point until he beats the likes of Shane or Floyd. Floyd I'm not 100% sold on either....only b/c his resume doesn't support him being a TOP WW...but his skills and talent do.

 

how can this kind of questions be asked? the current elite welters now are pac, floyd and mosley. cotto more probably is still an elite but back then in 2008 he was the best WW when he beat mosley.

 

He is elite...

But this poll wouldn't prove a thing, except what I have said all along (and somewhat proved)... He has more diehard followers than anyone on this board. Bar none.

http://www.eastsideboxing.com/forum/showthread.php?t=207257&highlight=rain+OR+shine

 

No. He was recognized as the best. But there were still two WW's who would have gladly whipped his ass.


One was a brickmason and the other... Well , I hate to sound like a broken record... so I'll leave that one alone.

 

He has a lot of fans but that doesnt change the fact that you ****ed up leaving Mosley out of that poll for a guy(Willy) that ended up with three votes.

Many guys that would vote for Sugar ended up voting for Cotto instead.

 

No.

It's disrespectful to put him with the all-time elites at welterweight.

 

and you seemed to forgot that cotto has been putting on an a clinic for the first 6 rounds versus margo. and i don't know who are you talking if it is clottey or floyd.